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+This file lists subtle things that might not be commented 
+as well as they should be in the source code and that
+might be worth pointing out in a longer explanation or in class.
+
+---
+
+forkret1 in trapasm.S is called with a tf argument.
+In order to use it, forkret1 copies the tf pointer into
+%esp and then jumps to trapret, which pops the 
+register state out of the trap frame.  If an interrupt
+came in between the mov tf, %esp and the iret that
+goes back out to user space, the interrupt stack frame
+would end up scribbling over the tf and whatever memory
+lay under it.
+
+Why is this safe?  Because forkret1 is only called
+the first time a process returns to user space, and
+at that point, cp->tf is set to point to a trap frame
+constructed at the top of cp's kernel stack.  So tf 
+*is* a valid %esp that can hold interrupt state.
+
+If other tf's were used in forkret1, we could add
+a cli before the mov tf, %esp.
+
+---
+
+In pushcli, must cli() no matter what.  It is not safe to do
+
+  if(cpus[cpu()].ncli == 0)
+    cli();
+  cpus[cpu()].ncli++;
+
+because if interrupts are off then we might call cpu(), get
+rescheduled to a different cpu, look at cpus[oldcpu].ncli,
+and wrongly decide not to disable interrupts on the new cpu.
+
+Instead do 
+
+  cli();
+  cpus[cpu()].ncli++;
+
+always.
+
+---
+
+There is a (harmless) race in pushcli, which does
+
+	eflags = read_eflags();
+	cli();
+	if(cpus[cpu()].ncli++ == 0)
+		cpus[cpu()].intena = eflags & FL_IF;
+
+Consider a bottom-level pushcli.  
+If interrupts are disabled already, then the right thing
+happens: read_eflags finds that FL_IF is not set,
+and intena = 1.  If interrupts are enabled, then
+it is less clear that the right thing happens:
+the read_eflags can execute, then the process
+can get preempted and rescheduled on another cpu,
+and then once it starts running, perhaps with 
+interrupts disabled (can happen since the scheduler
+only disables interrupts once per scheduling loop,
+not every time it schedules a process), it will 
+incorrectly record that interrupts *were* enabled.
+This doesn't matter, because if it was safe to be
+running with interrupts enabled before the context
+switch, it is still safe (and arguably more correct)
+to run with them enabled after the context switch too.
+
+In fact it would be safe if scheduler always set
+	c->intena = 1;
+before calling swtch, and perhaps it should.
+
+---
+
+The x86's processor-ordering memory model 
+matches spin locks well, so no explicit memory
+synchronization instructions are required in
+acquire and release.  
+
+Consider two sequences of code on different CPUs:
+
+CPU0
+A;
+release(lk);
+
+and
+
+CPU1
+acquire(lk);
+B;
+
+We want to make sure that:
+  - all reads in B see the effects of writes in A.
+  - all reads in A do *not* see the effects of writes in B.
+ 
+The x86 guarantees that writes in A will go out
+to memory before the write of lk->locked = 0 in 
+release(lk).  It further guarantees that CPU1 
+will observe CPU0's write of lk->locked = 0 only
+after observing the earlier writes by CPU0.
+So any reads in B are guaranteed to observe the
+effects of writes in A.
+
+Not sure about the second one yet.
+