148 lines
4 KiB
C
148 lines
4 KiB
C
/* $NetBSD: md5crypt.c,v 1.12 2012/08/30 12:16:49 drochner Exp $ */
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/*
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* ----------------------------------------------------------------------------
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* "THE BEER-WARE LICENSE" (Revision 42):
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* <phk@login.dknet.dk> wrote this file. As long as you retain this notice you
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* can do whatever you want with this stuff. If we meet some day, and you think
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* this stuff is worth it, you can buy me a beer in return. Poul-Henning Kamp
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* ----------------------------------------------------------------------------
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*
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* from FreeBSD: crypt.c,v 1.5 1996/10/14 08:34:02 phk Exp
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* via OpenBSD: md5crypt.c,v 1.9 1997/07/23 20:58:27 kstailey Exp
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*
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*/
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#include <sys/cdefs.h>
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#if !defined(lint)
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__RCSID("$NetBSD: md5crypt.c,v 1.12 2012/08/30 12:16:49 drochner Exp $");
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#endif /* not lint */
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#include <unistd.h>
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#include <stdio.h>
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#include <string.h>
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#include <md5.h>
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#include "crypt.h"
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#define MD5_MAGIC "$1$"
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#define MD5_MAGIC_LEN 3
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#define INIT(x) MD5Init((x))
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#define UPDATE(x, b, l) MD5Update((x), (b), (l))
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#define FINAL(v, x) MD5Final((v), (x))
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/*
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* MD5 password encryption.
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*/
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char *
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__md5crypt(const char *pw, const char *salt)
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{
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static char passwd[120], *p;
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const char *sp, *ep;
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unsigned char final[16];
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unsigned int i, sl, pwl;
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MD5_CTX ctx, ctx1;
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u_int32_t l;
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int pl;
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pwl = strlen(pw);
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/* Refine the salt first */
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sp = salt;
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/* If it starts with the magic string, then skip that */
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if (strncmp(sp, MD5_MAGIC, MD5_MAGIC_LEN) == 0)
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sp += MD5_MAGIC_LEN;
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/* It stops at the first '$', max 8 chars */
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for (ep = sp; *ep != '\0' && *ep != '$' && ep < (sp + 8); ep++)
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continue;
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/* get the length of the true salt */
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sl = ep - sp;
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INIT(&ctx);
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/* The password first, since that is what is most unknown */
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UPDATE(&ctx, (const unsigned char *)pw, pwl);
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/* Then our magic string */
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UPDATE(&ctx, (const unsigned char *)MD5_MAGIC, MD5_MAGIC_LEN);
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/* Then the raw salt */
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UPDATE(&ctx, (const unsigned char *)sp, sl);
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/* Then just as many characters of the MD5(pw,salt,pw) */
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INIT(&ctx1);
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UPDATE(&ctx1, (const unsigned char *)pw, pwl);
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UPDATE(&ctx1, (const unsigned char *)sp, sl);
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UPDATE(&ctx1, (const unsigned char *)pw, pwl);
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FINAL(final, &ctx1);
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for (pl = pwl; pl > 0; pl -= 16)
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UPDATE(&ctx, final, (unsigned int)(pl > 16 ? 16 : pl));
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/* Don't leave anything around in vm they could use. */
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memset(final, 0, sizeof(final));
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/* Then something really weird... */
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for (i = pwl; i != 0; i >>= 1)
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if ((i & 1) != 0)
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UPDATE(&ctx, final, 1);
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else
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UPDATE(&ctx, (const unsigned char *)pw, 1);
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/* Now make the output string */
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memcpy(passwd, MD5_MAGIC, MD5_MAGIC_LEN);
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strlcpy(passwd + MD5_MAGIC_LEN, sp, sl + 1);
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strlcat(passwd, "$", sizeof(passwd));
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FINAL(final, &ctx);
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/* memset(&ctx, 0, sizeof(ctx)); done by MD5Final() */
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/*
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* And now, just to make sure things don't run too fast. On a 60 MHz
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* Pentium this takes 34 msec, so you would need 30 seconds to build
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* a 1000 entry dictionary...
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*/
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for (i = 0; i < 1000; i++) {
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INIT(&ctx1);
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if ((i & 1) != 0)
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UPDATE(&ctx1, (const unsigned char *)pw, pwl);
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else
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UPDATE(&ctx1, final, 16);
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if ((i % 3) != 0)
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UPDATE(&ctx1, (const unsigned char *)sp, sl);
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if ((i % 7) != 0)
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UPDATE(&ctx1, (const unsigned char *)pw, pwl);
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if ((i & 1) != 0)
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UPDATE(&ctx1, final, 16);
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else
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UPDATE(&ctx1, (const unsigned char *)pw, pwl);
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FINAL(final, &ctx1);
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}
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/* memset(&ctx1, 0, sizeof(ctx1)); done by MD5Final() */
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p = passwd + sl + MD5_MAGIC_LEN + 1;
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l = (final[ 0]<<16) | (final[ 6]<<8) | final[12]; __crypt_to64(p,l,4); p += 4;
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l = (final[ 1]<<16) | (final[ 7]<<8) | final[13]; __crypt_to64(p,l,4); p += 4;
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l = (final[ 2]<<16) | (final[ 8]<<8) | final[14]; __crypt_to64(p,l,4); p += 4;
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l = (final[ 3]<<16) | (final[ 9]<<8) | final[15]; __crypt_to64(p,l,4); p += 4;
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l = (final[ 4]<<16) | (final[10]<<8) | final[ 5]; __crypt_to64(p,l,4); p += 4;
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l = final[11] ; __crypt_to64(p,l,2); p += 2;
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*p = '\0';
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/* Don't leave anything around in vm they could use. */
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__explicit_bzero(final, sizeof(final));
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return (passwd);
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}
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