ARM: Differentiate between LDM exception return and LDM user regs.

This commit is contained in:
Ali Saidi 2009-11-17 18:02:08 -06:00
parent 1470dae8e9
commit 0916c376a9

View file

@ -210,7 +210,9 @@ inline %(class_name)s::%(class_name)s(ExtMachInst machInst)
microOps[0] = new MicroAddiUop(machInst, INTREG_UREG0, RN, 0);
unsigned reg = 0;
bool forceUser = machInst.puswl.psruser;
bool force_user = machInst.puswl.psruser & !OPCODE_15;
bool exception_ret = machInst.puswl.psruser & OPCODE_15;
for (int i = 1; i < ones + 1; i++) {
// Find the next register.
while (!bits(regs, reg))
@ -218,12 +220,12 @@ inline %(class_name)s::%(class_name)s(ExtMachInst machInst)
replaceBits(regs, reg, 0);
unsigned regIdx = reg;
if (forceUser) {
if (force_user) {
regIdx = intRegForceUser(regIdx);
}
if (machInst.puswl.loadOp) {
if (reg == INTREG_PC && forceUser) {
if (reg == INTREG_PC && exception_ret) {
// This must be the exception return form of ldm.
microOps[i] =
new MicroLdrRetUop(machInst, regIdx, INTREG_UREG0, addr);